POJ_1251_kruskal
- 处理输入输出格式+kruskal
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55#include <iostream>
#include <algorithm>
using namespace std;
const int maxn = 100;
int n;
struct node {
int from,to,div;
node () {}
node (int u,int v,int w) {
from = u; to = v; w = div;
}
bool operator<(const node& temp) const{
return this->div < temp.div;
}
}e[maxn];
int pre[maxn];
int find(int x) {
if (x == pre[x]) return x;
else return pre[x] = find(pre[x]);
}
int main() {
// freopen("a.txt","r",stdin);
while (scanf("%d",&n) && n) {
int cnt = 0;
for (int i=1; i<=n; i++) pre[i] = i;
for (int i=1; i<=n-1; i++) {
char ch; int k;
scanf("\n%c %d",&ch,&k);
int cur = ch - 'A' + 1;
for (int j=1; j<=k; j++) {
int to,div;
scanf(" %c %d",&ch,&div);
to = ch - 'A' + 1;
e[cnt].from = cur; e[cnt].to = to; e[cnt].div = div;
cnt++;
}
}
sort(e,e+cnt);
int ans = 0;
for (int i=0; i<cnt; i++) {
int from = e[i].from;
int to = e[i].to;
if ( find(from) != find(to) ) {
ans += e[i].div;
pre[find(from)] = find(to);
}
}
cout << ans << endl;
}
return 0;
}
本博客所有文章除特别声明外,均采用 CC BY-SA 4.0 协议 ,转载请注明出处!